发布于 2016-05-02 09:45:52 | 162 次阅读 | 评论: 0 | 来源: 网友投递
这里有新鲜出炉的SQL Server教程,程序狗速度看过来!
SQL Server 数据库
SQL Server 即 Microsoft SQL Server 。
SQL是英文Structured Query Language的缩写,意思为结构化查询语言。SQL语言的主要功能就是同各种数据库建立联系,进行沟通。按照ANSI(美国国家标准协会)的规定,SQL被作为关系型数据库管理系统的标准语言。
SELECT SO.NAME AS "Table Name", SC.NAME AS "Column Name", SM.TEXT AS "Default Value"
FROM dbo.sysobjects SO INNER JOIN dbo.syscolumns SC ON SO.id = SC.id
LEFT JOIN dbo.syscomments SM ON SC.cdefault = SM.id
WHERE SO.xtype = 'U'
ORDER BY SO.[name], SC.colid
SELECT SO.NAME AS "Table Name", SC.NAME AS "Column Name", SM.TEXT AS "Default Value"
FROM dbo.sysobjects SO INNER JOIN dbo.syscolumns SC ON SO.id = SC.id
LEFT JOIN dbo.syscomments SM ON SC.cdefault = SM.id
WHERE SO.xtype = 'U' AND SM.TEXT IS NOT NULL
ORDER BY SO.[name], SC.colid
SELECT SO.NAME AS "Table Name", SC.NAME AS "Column Name", SM.TEXT AS "Default Value"
FROM dbo.sysobjects SO INNER JOIN dbo.syscolumns SC ON SO.id = SC.id
INNER JOIN dbo.syscomments SM ON SC.cdefault = SM.id
WHERE SO.xtype = 'U'
ORDER BY SO.[name], SC.colid
SELECT ST.[name] AS "Table Name", SC.[name] AS "Column Name", SD.definition AS "Default Value", SD.[name] AS "Constraint Name"
FROM sys.tables ST INNER JOIN sys.syscolumns SC ON ST.[object_id] = SC.[id]
INNER JOIN sys.default_constraints SD ON ST.[object_id] = SD.[parent_object_id] AND SC.colid = SD.parent_column_id
ORDER BY ST.[name], SC.colid